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Electronics & Antennas for Ham Radio

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Thevenin Equivalents in Receive Systems

—Why They Matter More on RX Than TX

Related reading:
The Truth About Low Noise Figures — Why MMICs Beat Low-NF Op-Amps in Real-World Antennas
High-Q vs Low-Q — The Secret Sauce Behind Antenna Efficiency and Bandwidth
The Illusion of Resonance — Appearance vs Reality

Thevenin is especially handy on the receive (Rx) side. On transmit (Tx) we care about power capability, efficiency, and non-linear behavior of PAs. On receive, signals are tiny, everything is linear, and noise + impedance dominate — exactly where the Thevenin model shines.

The One-Port That Rules Your RX Front End

Any antenna feedpoint can be modeled as:

[Vant]──[Zant]──► (feedline / LNA / receiver)

  • Vant ≡ antenna’s open-circuit RF voltage from the incident field.
  • Zant ≡ antenna feedpoint impedance = R + jX.

The Norton equivalent (a current source in parallel with Zant) is interchangeable, but the Thevenin form suits voltage-input LNAs and receivers best.

The Norton equivalent (a current source in parallel with Z is fully interchangeable with the Thevenin form. We often present receivers in Thevenin form because many LNA inputs are voltage‑sensing and 50‑Ω test gear is naturally series‑resistance based. That said, the Norton picture absolutely still applies—especially for current‑mode RX front ends—and remains highly relevant on the TX side, where PA devices, current‑steering DACs, and mixer outputs are well modeled as current sources feeding a load network. Choose the representation that matches what the next stage senses; the underlying match and delivered power are unchanged.

Why it matters: the entire RX chain can be reduced to two parameters — Vant and Zant — making it easy to compute delivered signal, noise, and SNR.

From Field Strength to Microvolts and dBm

A plane wave of field E (V/m) delivers power to the antenna through its effective aperture Ae = λ²G / (4π).

Power flux: S = E² / η (η ≈ 377 Ω).
Available power: Pavail = S Ae = E² Ae/η.

In Thevenin form:

Pavail = Vant² / (4 Rant) → Vant = 2√(PavailRant) = E·heff, where heff = 2√(RantAe/η).

Example 1 — HF 40 m Dipole:
G ≈ 1.64 (2.15 dBi), Rant ≈ 73 Ω, λ ≈ 42.9 m → Ae ≈ 239 m². For E = 1 µV/m: Pavail ≈ 6.3×10⁻¹³ W = −92 dBm, Vant ≈ 13.6 µV RMS.

Example 2 — VHF 2 m Yagi (12 dBi):
G = 15.85, R ≈ 50 Ω, λ ≈ 2.08 m → Ae ≈ 5.5 m². For E = 1 µV/m: Pavail ≈ 1.4×10⁻¹⁴ W = −108 dBm, Vant ≈ 1.7 µV RMS.

RX work lives in microvolts and −90 to −130 dBm. Thevenin turns that into a solvable two-number problem.

Noise and SNR — Why Thevenin Shines on RX

Any resistive source at T produces thermal noise power Pₙ = kTB and open-circuit noise voltage eₙ = √(4kTRB). At 290 K, the baseline is −174 dBm/Hz.

Antenna SNR = Psignal,avail / (k Tant B). Two key regimes:

  • External-noise-dominated (HF & below) — Tant ≫ Trx; lossless mismatch barely affects SNR.
  • Receiver-noise-dominated (VHF/SHF) — Tant ≈ few hundred K; feedline loss before LNA directly costs SNR.

Loss placement rule (Friis simplified):
Tsys ≈ Tant + (L−1)·290 + L·TLNA + … → Place the LNA at the antenna when you’re not external-noise-limited.

Matching: Power vs Noise

  • Power match (ZL = ZS*) maximizes delivered power.
  • Noise match sets ZS = Zopt of the LNA for minimum NF (often ≠ 50 Ω).
  • Lossless networks preserve SNR; resistive ones reduce it if receiver noise matters.

Mismatch factor τ = 1 − |Γ|². Signal and external noise scale with τ, internal noise does not — so mismatch hurts only in quiet, receiver-noise-dominated bands.

Designing a Better RX Chain (Step-by-Step)

  1. Measure Zant(f) with a VNA → that’s your Thevenin impedance.
  2. Estimate field → Ae → Pavail → Vant.
  3. Determine noise regime (HF vs VHF/SHF).
  4. Minimize loss before LNA if receiver-noise-limited.
  5. Choose matching goal (50 Ω power match or Zopt noise match).
  6. Use lossless L/π/T networks or transformers.
  7. Verify voltages and currents so the LNA is not overdriven.

Mini-Example — HF 40 m Dipole: ~73 Ω → 1:1 balun + coax → receiver; no LNA needed. Mini-Example — VHF 2 m Yagi: ~50 Ω → match to LNA’s Zopt with low-loss L-network at antenna.

What About Transmit?

The same equations predict delivered power and SWR, but transmit adds non-linearity and efficiency limits. On TX we’re power-limited, not noise-limited — so Thevenin is useful for matching and reflection math, not as a daily design tool.

Quick RX Cheat Sheet

  • Pavail = (E²/η)Ae, Ae = λ²G/(4π).
  • Vant = 2√(PavailRant) = E heff, heff = 2√(RantAe/η).
  • Thermal noise = kTB (−174 dBm/Hz at 290 K).
  • Loss before LNA adds Tloss = (L−1)·290 K.
  • Mismatch factor τ = 1 − |Γ|².

Common Pitfalls

  • Ignoring frequency dependence of Zant(f) and G(f).
  • Neglecting common-mode currents on coax — use baluns/chokes.
  • Using lossy pads in quiet bands where NF matters.
  • Assuming 50 Ω is always optimal on RX — it isn’t when noise matching rules.

Bottom Line

Thevenin modeling is most valuable on receive: it quantifies signal, noise, and SNR at the antenna port and guides where to place loss and how to match impedances. On transmit it still applies mathematically but efficiency and linearity take over as the dominant constraints.

Mini-FAQ

  • Is Thevenin modeling valid for broadband antennas? — Yes, but only locally in frequency; recompute for each band segment.
  • Does mismatch always hurt receive SNR? — Only when receiver noise dominates; in HF bands external noise dwarfs it.
  • Can I use Norton instead? — Absolutely; it’s the same model in current form — whichever simplifies your math.
  • Where should the LNA go? — As close to the antenna as possible unless you’re external-noise-limited.

Interested in more technical content? Subscribe to our updates for deep-dive RF articles and lab notes.

Questions or experiences to share? Contact RF.Guru — we’re always happy to discuss real-world RX challenges.

Written by Joeri Van Dooren, ON6URE — RF engineer, antenna designer, and founder of RF.Guru, specializing in high-performance HF/VHF antennas and RF components.

 

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